Optimal. Leaf size=91 \[ \frac {A (e x)^{m+1} \, _2F_1\left (2,\frac {m+1}{2};\frac {m+3}{2};-\frac {c x^2}{a}\right )}{a^2 e (m+1)}+\frac {B (e x)^{m+2} \, _2F_1\left (2,\frac {m+2}{2};\frac {m+4}{2};-\frac {c x^2}{a}\right )}{a^2 e^2 (m+2)} \]
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Rubi [A] time = 0.04, antiderivative size = 91, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {808, 364} \[ \frac {A (e x)^{m+1} \, _2F_1\left (2,\frac {m+1}{2};\frac {m+3}{2};-\frac {c x^2}{a}\right )}{a^2 e (m+1)}+\frac {B (e x)^{m+2} \, _2F_1\left (2,\frac {m+2}{2};\frac {m+4}{2};-\frac {c x^2}{a}\right )}{a^2 e^2 (m+2)} \]
Antiderivative was successfully verified.
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Rule 364
Rule 808
Rubi steps
\begin {align*} \int \frac {(e x)^m (A+B x)}{\left (a+c x^2\right )^2} \, dx &=A \int \frac {(e x)^m}{\left (a+c x^2\right )^2} \, dx+\frac {B \int \frac {(e x)^{1+m}}{\left (a+c x^2\right )^2} \, dx}{e}\\ &=\frac {A (e x)^{1+m} \, _2F_1\left (2,\frac {1+m}{2};\frac {3+m}{2};-\frac {c x^2}{a}\right )}{a^2 e (1+m)}+\frac {B (e x)^{2+m} \, _2F_1\left (2,\frac {2+m}{2};\frac {4+m}{2};-\frac {c x^2}{a}\right )}{a^2 e^2 (2+m)}\\ \end {align*}
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Mathematica [A] time = 0.03, size = 82, normalized size = 0.90 \[ \frac {x (e x)^m \left (A (m+2) \, _2F_1\left (2,\frac {m+1}{2};\frac {m+3}{2};-\frac {c x^2}{a}\right )+B (m+1) x \, _2F_1\left (2,\frac {m}{2}+1;\frac {m}{2}+2;-\frac {c x^2}{a}\right )\right )}{a^2 (m+1) (m+2)} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.16, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (B x + A\right )} \left (e x\right )^{m}}{c^{2} x^{4} + 2 \, a c x^{2} + a^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B x + A\right )} \left (e x\right )^{m}}{{\left (c x^{2} + a\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.66, size = 0, normalized size = 0.00 \[ \int \frac {\left (B x +A \right ) \left (e x \right )^{m}}{\left (c \,x^{2}+a \right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B x + A\right )} \left (e x\right )^{m}}{{\left (c x^{2} + a\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (e\,x\right )}^m\,\left (A+B\,x\right )}{{\left (c\,x^2+a\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 34.16, size = 770, normalized size = 8.46 \[ A \left (- \frac {a e^{m} m^{2} x x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {2 a e^{m} m x x^{m} \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {a e^{m} x x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {2 a e^{m} x x^{m} \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} - \frac {c e^{m} m^{2} x^{3} x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {c e^{m} x^{3} x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}\right ) + B \left (- \frac {a e^{m} m^{2} x^{2} x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + 1\right ) \Gamma \left (\frac {m}{2} + 1\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + 2\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + 2\right )} - \frac {2 a e^{m} m x^{2} x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + 1\right ) \Gamma \left (\frac {m}{2} + 1\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + 2\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + 2\right )} + \frac {2 a e^{m} m x^{2} x^{m} \Gamma \left (\frac {m}{2} + 1\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + 2\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + 2\right )} + \frac {4 a e^{m} x^{2} x^{m} \Gamma \left (\frac {m}{2} + 1\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + 2\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + 2\right )} - \frac {c e^{m} m^{2} x^{4} x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + 1\right ) \Gamma \left (\frac {m}{2} + 1\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + 2\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + 2\right )} - \frac {2 c e^{m} m x^{4} x^{m} \Phi \left (\frac {c x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + 1\right ) \Gamma \left (\frac {m}{2} + 1\right )}{8 a^{3} \Gamma \left (\frac {m}{2} + 2\right ) + 8 a^{2} c x^{2} \Gamma \left (\frac {m}{2} + 2\right )}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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